确定对象和数组中的值之间的差异

我有以下对象和数字数组。如何判断数组中的哪个数字不作为对象中的 id 存在？在下面的示例中，我想要 1453。

[
  {id: 60, itemName: 'Main Location - 1100 Superior Road - Cleveland'}
  {id: 1456, itemName: 'Third Location - 107,West 20th Street,Manhattan - New York'}
]

[60, 1453, 1456]

对于更大数量的数据项和更大数量的id我会选择一种方法来创建Set https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Set基于查找通过map https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/mapping 每个itemList item's id...

const idLookup = new Set(itemList.map(({ id }) => id));

直接从 a 查找项目Set or a Map https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Map实例比例如快得多通过一次又一次迭代数组find https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find or includes https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/includes对于外部的每个迭代步骤filter https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter task.

过滤不匹配项目的列表 -id那么就很简单...

const listOfNonMatchingIds = idList.filter(id => !idLookup.has(id));

...示例代码...

const itemList = [
  { id: 60, itemName: 'Main Location - 1100 Superior Road - Cleveland' },
  { id: 1456, itemName: 'Third Location - 107,West 20th Street,Manhattan - New York' },
];
const idList = [60, 1453, 1456];

const idLookup = new Set(itemList.map(({ id }) => id));
const listOfNonMatchingIds = idList.filter(id => !idLookup.has(id));

console.log({ listOfNonMatchingIds });

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