我已经花了几个小时尝试这样做,但我永远无法获得我想要获得的数据。
我需要以其他方式提出请求吗?这是我的代码:
doGoogleLogin(){
return new Promise<any>((resolve, reject) => {
let provider = new firebase.auth.GoogleAuthProvider();
provider.addScope('profile');
provider.addScope('email');
provider.addScope('https://www.googleapis.com/auth/user.birthday.read');
provider.addScope('https://www.googleapis.com/auth/user.gender.read');
this.afAuth.auth
.signInWithPopup(provider)
.then(res => {
resolve(res);
console.log(res.additionalUserInfo.profile['id']);
this.http
.get("https://people.googleapis.com/v1/people/"+res.additionalUserInfo.profile['id']+"?key=(a valid api key)&personFields=birthdays,genders")
.subscribe(data => (console.log(data)));;
}, err => reject(err))
})
}
我通常从http请求中获取的数据只是:
{
"resourceName": "people/101296298961277932659",
"etag": "%EgQBBzcuGgQBAgUH"
}
我应该再得到 2 个包含出生日期和性别的对象,但它从未发生过。
使用 Sebas 他的答案,我成功地让 People API 与我的 Firebase 代码一起工作,我将在此处将其发布给其他人:
First 在开发者控制台中启用 API https://console.developers.google.com/apis/library/people.googleapis.com.
import firebase from 'firebase/app'
let provider = new firebase.auth.GoogleAuthProvider()
provider.addScope('profile')
provider.addScope('email')
provider.addScope('https://www.googleapis.com/auth/user.birthday.read')
provider.addScope('https://www.googleapis.com/auth/user.gender.read')
firebase
.auth()
.signInWithPopup(provider)
.then(res => {
fetch(
`https://people.googleapis.com/v1/people/${res.additionalUserInfo.profile.id}?personFields=birthdays,genders&access_token=${res.credential.accessToken}`
).then(response => console.log(response))
})
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