嘿，再次，我仍然掌握查询和其他东西，所以请原谅所有常见的 SQL 问题 8)
无论如何，我试图选择某个值之后的行。
不明白？好吧，这就是它实际的样子。
表：消息
+------------+-----------+---------+-------+---------------------------------------+----------------+------------------+
| message_id | thread_id | user_id | to_id | body | message_status | uid_sent_deleted |
+------------+-----------+---------+-------+---------------------------------------+----------------+------------------+
| 1 | 1 | 1 | 7 | How are you bro? | read | 1 |
| 2 | 1 | 7 | 1 | IM good what about you kenny? | read | 0 |
| 3 | 1 | 1 | 7 | Same just chilling how is your sister | read | 1 |
| 4 | 1 | 7 | 1 | Shes coool u know just doin great | read | 0 |
| 7 | 1 | 1 | 7 | Thats nice | read | 1 |
| 8 | 1 | 7 | 1 | Yupp | read | 0 |
| 9 | 1 | 1 | 7 | hhahaha | read | 1 |
| 10 | 1 | 7 | 1 | anyways.... | unread | 0 |
+------------+-----------+---------+-------+---------------------------------------+----------------+------------------+
如果消息 ID 为 9，则 uid_sent_deleted 列中的值为“1”。
我试图选择 uid_sent_deleted 列中值为“1”的最后一行之后的行。
这是我当前正在使用的sql。谢谢您的帮助！！
SELECT message_id, thread_id, messages.user_id, to_id, body, message_status, uid_sent_deleted
FROM messages
INNER JOIN messages_thread ON messages_thread.id = messages.thread_id
WHERE thread_id =1
GROUP BY messages.message_id
ORDER BY message_id ASC
... WHERE thread_id = 1 AND id >
(SELECT MAX(id) FROM messages WHERE uid_sent_deleted = 1)
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