如何获取 Quartz 用于描边 NSBezierPath 的路径

我使用这段代码用一条宽的黑色虚线来描画 NSBezierPath。

(c and strForBezier在其他地方定义）

NSGlyph glyph;
for(n = 0; n < len; n++) {
    glyph = [font glyphWithName: [strForBezier substringWithRange:NSMakeRange(n, 1)]];
    [path appendBezierPathWithGlyph: glyph inFont: font];
}

CGFloat pattern2[4]; pattern2[0]=5*c; pattern2[1]=2*c; pattern2[2]=2*c; pattern2[3]=2*c;
[path setLineDash:pattern2 count:4 phase:0];

[path setLineWidth:c];
[path stroke];
[[NSColor blueColor] set ];
[path fill];

如何获得黑色 NSBezierPath ？我假设构建并填充了 NSBezierPath 以描画初始曲线。

您可以通过划线和描边现有路径来创建路径，但这需要使用CGPathRef代替NSBezierPath.

CGMutablePathRef path0 = CGPathCreateMutable();
CGAffineTransform transform = CGAffineTransformMakeTranslation(20, 20);
// initial position is {20, 20}

CGGlyph glyph;
for(n = 0; n < len; n++)
{
    glyph = [font glyphWithName: [strForBezier substringWithRange:NSMakeRange(n, 1)]];
    CGPathRef glyphPath = CTFontCreatePathForGlyph((__bridge CTFontRef) font, glyph, NULL);
    CGPathAddPath(path0, &transform, glyphPath);
    CGPathRelease(glyphPath);

    // append the glyph advance to the transform
    CGSize advance;
    CTFontGetAdvancesForGlyphs((__bridge CTFontRef) font, kCTFontDefaultOrientation, &glyph, &advance, 1);
    transform.tx += advance.width;
    transform.ty += advance.height;
}

CGFloat pattern2[4]; pattern2[0]=5*c; pattern2[1]=2*c; pattern2[2]=2*c; pattern2[3]=2*c;
CGPathRef path1 = CGPathCreateCopyByDashingPath(path0, NULL, 0, pattern2, 4);
CGPathRef path2 = CGPathCreateCopyByStrokingPath(path1, NULL, c, kCGLineCapButt, kCGLineJoinMiter, CGFLOAT_MAX);

CGContextRef context = [NSGraphicsContext currentContext].graphicsPort;
CGContextAddPath(context, path2);
CGContextDrawPath(context, kCGPathFill);

CGPathRelease(path0);
CGPathRelease(path1);
CGPathRelease(path2);

如果你不舒服CGPathRef，您可以创建一个NSBezierPath然后将其转换为CGPathRef使用Apple文档中描述的方法从 NSBezierPath 对象构建 CGPathRef https://developer.apple.com/library/mac/documentation/cocoa/Conceptual/CocoaDrawingGuide/Paths/Paths.html#//apple_ref/doc/uid/TP40003290-CH206-SW2（相反也是可能的）。