我有一个文本文件，如以下小示例：
chr1 HAVANA transcript 12010 13670 . + . gene_id "ENSG00000223972.4"; transcript_id "ENST00000450305.2"; gene_type "pseudogene"; gene_status "KNOWN"; gene_name "DDX11L1"; tr
anscript_type "transcribed_unprocessed_pseudogene"; transcript_status "KNOWN"; transcript_name "DDX11L1-001"; level 2; ont "PGO:0000005"; ont "PGO:0000019"; havana_gene "OTTHUMG00000000961.2"; havana_tran
script "OTTHUMT00000002844.2";
chr2 HAVANA exon 53 955 . + . gene_id "ENSG00000223972.4"; transcript_id "ENST00000450305.2"; gene_type "pseudogene"; gene_status "KNOWN"; gene_name "DDX11L1"; transcript
_type "transcribed_unprocessed_pseudogene"; transcript_status "KNOWN"; transcript_name "DDX11L1-001"; exon_number 1; exon_id "ENSE00001948541.1"; level 2; ont "PGO:0000005"; ont "PGO:0000019"; havana_gene
"OTTHUMG00000000961.2"; havana_transcript "OTTHUMT00000002844.2";
这个小例子的预期输出是：
chr1 HAVANA transcript 11998 12060 . + . gene_id "ENSG00000223972.4"; transcript_id "ENST00000450305.2"; gene_type "pseudogene"; gene_status "KNOWN"; gene_name "DDX11L1"; tr
anscript_type "transcribed_unprocessed_pseudogene"; transcript_status "KNOWN"; transcript_name "DDX11L1-001"; level 2; ont "PGO:0000005"; ont "PGO:0000019"; havana_gene "OTTHUMG00000000961.2"; havana_tran
script "OTTHUMT00000002844.2";
chr2 HAVANA exon 41 103 . + . gene_id "ENSG00000223972.4"; transcript_id "ENST00000450305.2"; gene_type "pseudogene"; gene_status "KNOWN"; gene_name "DDX11L1"; transcript
_type "transcribed_unprocessed_pseudogene"; transcript_status "KNOWN"; transcript_name "DDX11L1-001"; exon_number 1; exon_id "ENSE00001948541.1"; level 2; ont "PGO:0000005"; ont "PGO:0000019"; havana_gene
"OTTHUMG00000000961.2"; havana_transcript "OTTHUMT00000002844.2";
在输入文件中，有不同的行。每行开头为chr。每行都有一些列，分隔符是制表符或“;”。
我想从此文件创建一个新文件，其中仅第 4 列和第 5 列发生更改。事实上，新文件中的第 4 列将是((column 4 in original file)-12)新文件中的第五列是((column 4 in original file)+50)。输入文件和输出文件之间的唯一区别在于第四列和第五列的数字。
我尝试这样做awk使用以下命令：
awk 'BEGIN { FS="\t;" } {print $1"\t"$2"\t"$3"\t"$4=$4-12"\t"$5=$4+50"\t"$6"\t"$7"\t"$8"\t"$9" "$10";"$11" "$12";"$13" "$14";"$15" "$16";"$17" "$18";"$19" "$20";"$21" "$22";"$23" "$24";"$25" "$26";"$27" "$28";"$29" "$30";"$31" "$32";"$33" "$34";"$35" "$36";"$37" "$38";" }' input.txt > test2.txt
当我运行代码时，它会返回以下错误：
awk: cmd. line:1: BEGIN { FS="\t;" } {print $1"\t"$2"\t"$3"\t"$4=$4-12"\t"$5=$4+50"\t"$6"\t"$7"\t"$8"\t"$9" "$10";"$11" "$12";"$13" "$14";"$15" "$16";"$17" "$18";"$19" "$20";"$21" "$22";"$23" "$24";"$25" "$26";"$27" "$28";"$29" "$30";"$31" "$32 ";" $33" "$34";"$35" "$36";"$37" "$38";" }
awk: cmd. line:1: ^ syntax error
awk: cmd. line:1: BEGIN { FS="\t;" } {print $1"\t"$2"\t"$3"\t"$4=$4-12"\t"$5=$4+50"\t"$6"\t"$7"\t"$8"\t"$9" "$10";"$11" "$12";"$13" "$14";"$15" "$16";"$17" "$18";"$19" "$20";"$21" "$22";"$23" "$24";"$25" "$26";"$27" "$28";"$29" "$30";"$31" "$32 ";" $33" "$34";"$35" "$36";"$37" "$38";" }
awk: cmd. line:1: ^ syntax error
你知道如何修复它吗？我想获得与输入文件格式完全相同的输出文件。表示相同的分隔符。
不需要单独输出每一列，修改现有数据然后打印修改后的行就足够了。
awk -F '\t' '{ col4 = $4; $4 = col4 - 12; $5 = col4 + 50; print }' OFS='\t' file
这会在打印整行之前修改第四和第五个制表符分隔的列。
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