将 PowerShell 变量传递到脚本块

我正在尝试获取 PowerShell 变量并将它们应用到脚本块。

param(
    [string]$username = $(throw "Blackberry Admin User Name is required"),
    [string]$password = $(throw "Blackberry Admin Password is required"),
    [string]$u = $(throw "Blackberry User Name is required")
    )
        
$s = New-PSSession -computerName bbbes01 
Invoke-Command -Session $s -Scriptblock {cd "C:\Program Files (x86)\Research In Motion\BlackBerry Enterprise Server Resource Kit\BlackBerry Enterprise Server User Administration Tool Client"
./BESUserAdminClient -username $username -password $password -ad_auth -domain staging -b bbbes -u $u -change -wrandom} -argumentlist $username $password $u

我在跑步

.\RandomActivationEmail.ps1 -username besadmin -password Pa$$word -u bb.user

我收到的错误是：

Invoke-Command：找不到接受参数“Pa$$word”的位置参数。 在 C:\Scripts\bb\RandomActivationEmail.ps1:12 字符:15
+ Invoke-Command + CategoryInfo : InvalidArgument: (:) [Invoke-Command], ParameterBindingException
+ FullQualifiedErrorId：PositionalParameterNotFound、Microsoft.PowerShell.Commands.InvokeCommandCommand

您可以通过 -arguments 参数传递值，并在脚本块内将它们引用为 $args[0] 等：

Invoke-Command -Session $s -Scriptblock {
    cd "C:\Program Files (x86)\Research In Motion\BlackBerry Enterprise Server Resource Kit\BlackBerry Enterprise Server User Administration Tool Client"
    ./BESUserAdminClient -username $args[0] -password $args[1] -ad_auth -domain staging -b bbbes -u $args[2] -change -wrandom
} -argumentlist $username $password $u

或者在脚本块内定义参数并使用命名参数：

Invoke-Command -Session $s -Scriptblock {
    param(
        $username,$password,$u
    )

    cd "C:\Program Files (x86)\Research In Motion\BlackBerry Enterprise Server Resource Kit\BlackBerry Enterprise Server User Administration Tool Client"
    ./BESUserAdminClient -username $username -password $password  -ad_auth -domain staging -b bbbes -u $u -change -wrandom
} -argumentlist $username $password $u