我有 2 个配置文件模型。我正在创建一个“与会者”对象。如何仅在 2 个配置文件之间进行过滤?
class Profile1(models.Model):
user = models.ForeignKey(User, null=True, unique=True)
class Profile2(models.Model):
user = models.ForeignKey(User, null=True, unique=True)
class Attendee(models.Model):
event = models.ForeignKey(Event)
# This filters through everything... How do I filter down just to the 2 profile objects?
content_type = models.ForeignKey(ContentType)
object_id = models.PositiveIntegerField()
profile = generic.GenericForeignKey('content_type', 'object_id')
感谢您的帮助!
As 内容类型模型 https://docs.djangoproject.com/en/dev/ref/contrib/contenttypes/#the-contenttype-model有三个字段app_label
, model
and name
。因此您可以轻松地过滤这些字段。
attendees = Attendee.objects.filter(content_type__model = 'Profile1')
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