如何在SQL中按任意条件排序

我有下表：

CREATE TABLE Bable
    (
     id int identity primary key, 
     name varchar(20), 
     about varchar(30)
    );
INSERT INTO Bable (name,about) VALUES
('ООО Name Firm 1','texttexttexttext'),
('ООО Name Firm 2','texttexttexttext'),
('ООО Name Firm 3','texttexttexttext'),
('ООО Name Firm 4','texttexttexttext'),
('ООО Name Firm 5','texttexttexttext'),
('ООО Name Firm $1','texttexttexttext'),
('ООО Name Firm $2','texttexttexttext'),
('ООО Name Firm $3','texttexttexttext'),
('ООО Name Firm 6','texttexttexttext'),
('ООО Name Firm 7','texttexttexttext')

我可以编写如下查询：

SELECT * FROM Bable WHERE about = 'texttexttexttext'

如何更改此查询以返回排序的结果，使得名称中包含“$”的结果首先出现，然后是不包含“$”的结果，然后按每个组排序name上升？

表的结构在这里 http://sqlfiddle.com/#!3/14d86

SELECT *
FROM   Bable
ORDER  BY CASE WHEN name LIKE '%$..' THEN 0 ELSE 1 END,
          Name 

• SQLFiddle 演示 http://sqlfiddle.com/#!3/d1514/1