谢谢@Yuriy 重新打开这个,我已经从@Ingo Bürk 的评论中得到了答案。
下面提到的Gist帮助我通过正则表达式创建路线。https://gist.github.com/matanshukry/22fae5dba9c307baf0f364a9c9f7c115 https://gist.github.com/matanshukry/22fae5dba9c307baf0f364a9c9f7c115
作为参考,我添加了下面的来源,
/**
* Copyright (c) Matan Shukry
* All rights reserved.
*/
import { UrlSegment, UrlSegmentGroup, Route } from '@angular/router';
// export type UrlMatchResult = {
// consumed: UrlSegment[]; posParams?: { [name: string]: UrlSegment };
// };
export function ComplexUrlMatcher(paramName: string, regex: RegExp) {
return (
segments: UrlSegment[],
segmentGroup: UrlSegmentGroup,
route: Route) => {
const parts = [regex];
const posParams: { [key: string]: UrlSegment } = {};
const consumed: UrlSegment[] = [];
let currentIndex = 0;
for (let i = 0; i < parts.length; ++i) {
if (currentIndex >= segments.length) {
return null;
}
const current = segments[currentIndex];
const part = parts[i];
if (!part.test(current.path)) {
return null;
}
posParams[paramName] = current;
consumed.push(current);
currentIndex++;
}
if (route.pathMatch === 'full' &&
(segmentGroup.hasChildren() || currentIndex < segments.length)) {
return null;
}
return { consumed, posParams };
}
}
如何使用,
/**
* Copyright (c) Matan Shukry
* All rights reserved.
*/
export const UserRoutes: Routes = [
{
path: 'users',
component: UserComponent,
children: [
{
path: '',
component: UserListComponent
},
{
matcher: ComplexUrlMatcher("id", /[0-9]+/),
component: UserItemComponent
},
]
}
];
@NgModule({
imports: [RouterModule.forChild(UserRoutes)],
exports: [RouterModule]
})
export class UserRoutingModule { }