Python 3 从网络广播流中获取歌曲名称

如何从网络广播流中获取歌曲名称？

Python：从url获取shoutcast/网络广播电台的名称 https://stackoverflow.com/questions/3110494/python-get-name-of-shoutcast-internet-radio-station-from-url我看了这里，但只有广播电台的名称。但是如何获取正在播放的歌曲的名称呢？这是我想获取歌曲名称的流链接。http://pool.cdn.lagardere.cz/fm-evropa2-128 http://pool.cdn.lagardere.cz/fm-evropa2-128

我该怎么做呢？你能帮我吗？

要获取流标题，您需要请求元数据。看shoutcast/icecast 协议说明 http://www.smackfu.com/stuff/programming/shoutcast.html:

#!/usr/bin/env python
from __future__ import print_function
import re
import struct
import sys
try:
    import urllib2
except ImportError:  # Python 3
    import urllib.request as urllib2

url = 'http://pool.cdn.lagardere.cz/fm-evropa2-128'  # radio stream
encoding = 'latin1' # default: iso-8859-1 for mp3 and utf-8 for ogg streams
request = urllib2.Request(url, headers={'Icy-MetaData': 1})  # request metadata
response = urllib2.urlopen(request)
print(response.headers, file=sys.stderr)
metaint = int(response.headers['icy-metaint'])
for _ in range(10): # # title may be empty initially, try several times
    response.read(metaint)  # skip to metadata
    metadata_length = struct.unpack('B', response.read(1))[0] * 16  # length byte
    metadata = response.read(metadata_length).rstrip(b'\0')
    print(metadata, file=sys.stderr)
    # extract title from the metadata
    m = re.search(br"StreamTitle='([^']*)';", metadata)
    if m:
        title = m.group(1)
        if title:
            break
else: 
    sys.exit('no title found')
print(title.decode(encoding, errors='replace'))

在这种情况下，流标题为空。