使用带有 IN 子句的 query() 进行 CodeIgniter 数据库查询

我的模型中有以下代码：

$sql = "SELECT t1.*, t2.* FROM Table1 t1 INNER JOIN Table2 t2 ON t1.id = t2.id AND t2.title IN (?) AND t1.type = ? ORDER BY t1.id";
$q = $this->db->query( $sql, array( $filter, $type ) );

问题是这个查询在以下情况下工作正常：

$filter = 'a';

但如果出现以下情况则不返回任何内容：

$filter = "'a','b','c','d'";

对于第二种情况，我可以看到 CI 正在转义 $filter，如下所示：

SELECT t1.*, t2.* FROM Table1 t1 INNER JOIN Table2 t2 ON t1.id = t2.id AND t2.title IN ('\'a\',\'b\',\'c\',\'d\'') AND t1.type = ? ORDER BY t1.id

这是正确的行为。 CI 在将引号发送到 MySQL 之前对其进行转义。您可能应该使用一个数组作为过滤器并构造类似的东西（未经测试；））

$filter = array('a','b','c');
$sql = "SELECT t1.*, t2.* 
     FROM Table1 t1 
     INNER JOIN Table2 t2 
         ON  t1.id = t2.id 
         AND t2.title IN (". implode(',', array_fill(0, count($filter), '?')).") 
         AND t1.type = ? 
     ORDER BY t1.id";
//edit: check if $filter is not an array ( when it is a single value string )
$filter = is_array( $filter ) ? $filter : array( $filter );
$q = $this->db->query( $sql, array_merge( $filter, array( $type ) ) );

您还应该稍微重写一下查询：

$sql = "SELECT t1.*, t2.* 
     FROM Table1 t1 
     INNER JOIN Table2 t2 
         ON  t1.id = t2.id 
     WHERE
         t2.title IN (". implode(',', array_fill(0, count($filter), '?')).") 
         AND t1.type = ? 
     ORDER BY t1.id";