Python / Matplotlib -- 按一年中的某一天列出的日期直方图

我有一个跨越数百年的日期列表。我想制作一个包含 366 个桶的直方图，一个桶代表一年中的每一天，x 轴以清晰的方式标记，让我可以看到哪个日期是哪个日期（我预计 2 月 29 日会出现下降） ， 例如）。

我制作了以下直方图，但易于阅读的 X 轴日期标签会很棒。下面的代码看起来很麻烦，但得到了我想要的（没有 X 轴标签）：

from datetime import date, datetime, timedelta
from collections import Counter
import pylab


def plot_data(data):
    """data is a list of dicts that contain a field "date" with a datetime."""

    def get_day(d):
        return d.strftime("%B %d")  # e.g. January 01

    days = []
    n = 366
    start_date = date(2020, 1, 1)  # pick a leap year
    for i in range(n):
        d = start_date + timedelta(days=i)
        days.append(get_day(d))

    counts = Counter(get_day(d['date']) for d in data)
    
    Y = [counts.get(d) for d in days]
    X = list(range(len(days)))

    pylab.bar(X, Y)
    pylab.xlim([0, n])

    pylab.title("Dates day of year")
    pylab.xlabel("Day of Year (0-366)")
    pylab.ylabel("Count")
    pylab.savefig("Figure 1.png")

任何帮助缩短此时间并使 x 轴日期更加灵活和清晰的帮助将不胜感激！

UPDATE

我已将以下想法纳入以下要点 https://gist.github.com/jsundram/ef0543b7c86128faba2c81b887459eaf，它产生如下所示的输出：

尝试检查这段代码：

# import section
import pandas as pd
import matplotlib.pyplot as plt
import matplotlib.dates as md
import numpy as np
from datetime import date
from itertools import product

# generate a dataframe like yours
date = [date(2020, m, d).strftime("%B %d") for m, d in product(range(1, 13, 1), range(1, 29, 1))]
value = np.abs(np.random.randn(len(date)))
data = pd.DataFrame({'date': date,
                     'value': value})
data.set_index('date', inplace = True)

# convert index from str to date
data.index = pd.to_datetime(data.index, format = '%B %d')

# plot
fig, ax = plt.subplots(1, 1, figsize = (16, 8))
ax.bar(data.index,
       data['value'])

# formatting xaxis
ax.xaxis.set_major_locator(md.DayLocator(interval = 5))
ax.xaxis.set_major_formatter(md.DateFormatter('%B %d'))
plt.setp(ax.xaxis.get_majorticklabels(), rotation = 90)
ax.set_xlim([data.index[0], data.index[-1]])

plt.show()

这给了我这个情节：

我将数据帧的索引从字符串转换为日期，然后应用了我想要的 xaxis 格式ax.xaxis.set_major_locator and ax.xaxis.set_major_formatter方法。
为了绘制我使用的matplotlib，但将这种方法转化为应该不难pylab.

EDIT

如果您想要几天和几个月的单独刻度，您可以添加辅助轴（选中此example https://matplotlib.org/examples/axes_grid/demo_parasite_axes2.html）如这段代码所示：

# import section
import pandas as pd
import matplotlib.pyplot as plt
import matplotlib.dates as md
import numpy as np
from datetime import date
from itertools import product
from mpl_toolkits.axes_grid1 import host_subplot
import mpl_toolkits.axisartist as AA

# generate a dataframe like yours
date = [date(2020, m, d).strftime("%B %d") for m, d in product(range(1, 13, 1), range(1, 29, 1))]
value = np.abs(np.random.randn(len(date)))
data = pd.DataFrame({'date': date,
                     'value': value})
data.set_index('date', inplace = True)

# convert index from str to date
data.index = pd.to_datetime(data.index, format = '%B %d')

# prepare days and months axes
fig = plt.figure(figsize = (16, 8))
days = host_subplot(111, axes_class = AA.Axes, figure = fig)
plt.subplots_adjust(bottom = 0.1)
months = days.twiny()

# position months axis
offset = -20
new_fixed_axis = months.get_grid_helper().new_fixed_axis
months.axis['bottom'] = new_fixed_axis(loc = 'bottom',
                                       axes = months,
                                       offset = (0, offset))
months.axis['bottom'].toggle(all = True)

#plot
days.bar(data.index, data['value'])

# formatting days axis
days.xaxis.set_major_locator(md.DayLocator(interval = 10))
days.xaxis.set_major_formatter(md.DateFormatter('%d'))
plt.setp(days.xaxis.get_majorticklabels(), rotation = 0)
days.set_xlim([data.index[0], data.index[-1]])

# formatting months axis
months.xaxis.set_major_locator(md.MonthLocator())
months.xaxis.set_major_formatter(md.DateFormatter('%b'))
months.set_xlim([data.index[0], data.index[-1]])

plt.show()

产生这个图：