在我的应用程序中,我想修改各种mp3,然后将它们混合在一起。我知道我可以在 FFmpeg 中使用单个命令行来完成此操作,但它最终可能会非常混乱,因为我需要在每个样本上使用各种过滤器,而我有五个过滤器。
我的想法是单独编辑每个样本,将它们保存到变量中,最后混合它们。这是我的代码:
import subprocess
def create_samp():
sample= subprocess.run(["ffmpeg", "-y", "-i", "https://freesound.org/data/previews/186/186942_2594536-hq.mp3", \
"-filter_complex", "adelay=15000|15000", "-codec:v", "copy", "-f", "mp3","-"], stdout=subprocess.PIPE)
return(sample)
def record(samp):
subprocess.run(["ffmpeg", "-y", "-i", "https://cdns-preview-b.dzcdn.net/stream/c-b0b684fe962f93dc43f1f7ea493683a1-3.mp3", \
"-i", samp.stdout, "-f", "-mp3", "copy", "output.mp3"])
samp = create_samp()
record(samp)
我的问题是我必须编码stdout
。我试过了'utf-8'
但得到这个错误:
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xff in position 45: invalid start byte
使用“utf-16”:
UnicodeDecodeError: 'utf-16-le' codec can't decode bytes in position 239454-239455: illegal encoding
为什么有办法解决这个问题呢?我的方法正确吗?
感谢@Rotem,我成功地做了我想做的事。但现在我面临着另一个问题,因为我想混合最多 5 个声音,所以我尝试以懒惰/简单的方式实现它:
import subprocess
def create_samp_2():
sample= subprocess.run(["ffmpeg", "-i", "https://freesound.org/data/previews/186/186942_2594536-hq.mp3", \
"-af", "adelay=15000|15000", "-f", "mp3", "pipe:"], stdout=subprocess.PIPE).stdout
return(sample)
def create_samp():
sample= subprocess.run(["ffmpeg", "-i", "https://freesound.org/data/previews/370/370934_6399962-lq.ogg", \
"-af", "adelay=1000|1000", "-f", "mp3", "pipe:"], stdout=subprocess.PIPE).stdout
return(sample)
def record(samp, samp_2):
process = subprocess.Popen(["ffmpeg", "-y", '-f', 'mp3', \
"-i", "https://cdns-preview-b.dzcdn.net/stream/c-b0b684fe962f93dc43f1f7ea493683a1-3.mp3", \
"-i", "pipe:", \
"-i", "pipe:", \
"-filter_complex", "amix=inputs=3:duration=longest", "output.mp3"], stdin=subprocess.PIPE)
process.stdin.write(samp)
process.stdin.write(samp_2)
process.stdin.close()
process.wait()
samp = create_samp()
samp_2 = create_samp_2()
record(samp, samp_2)
令人惊讶的是它有效,我的两个声音在正确的时间开始,但第二个声音搞砸了。所以这不是正确的做法。
然后我按照建议尝试命名管道:
"pipe1:"
但我收到这个错误:
pipe1:: Protocol not found
Did you mean file:pipe1:?
阅读命名管道维基,据说我必须使用以下命令创建它们mkfifo()
.
所以我尝试:
import os
pipe1 = "pipe1"
def create_pipe1():
os.mkfifo(pipe1)
But now I have this error: pipe1:: Protocol not found
Did you mean file:pipe1:?