合计投票结果

我有一张选票，每个选民获得 3 票，从 10 名不同的候选人中进行选择。投票 1 得 3 分，投票 2 得 2 分，投票 3 得 1 分。

我有以下 SQL 查询来计算每次投票获得的总分（因此投票 1、2 和 3 的结果是分开的）。

我需要做的是将所有这些结果放在一个表中，但我不太确定从哪里开始。

SELECT cn.cand_name, (count(vote_1) * 3) as vote_1 FROM candidate_votes cv Inner Join candidate_names cn ON cv.vote_1 = cn.cand_number GROUP BY cand_name;

SELECT cn.cand_name, (count(vote_2) * 2) as vote_2 FROM candidate_votes cv Inner Join candidate_names cn ON cv.vote_2 = cn.cand_number GROUP BY cand_name;

SELECT cn.cand_name, (count(vote_3) * 1) as vote_3 FROM candidate_votes cv Inner Join candidate_names cn ON cv.vote_3 = cn.cand_number GROUP BY cand_name;

我有以下结果表：

Voter_number    Vote_1     Vote2      Vote3
123             cand_1     cand_3     cand_2
456             cand_2     cand_1     cand_3
789             cand_2     cand_3     cand_1

以及以下候选姓名表：

cand_number     cand_name
cand_1          Dave
cand_2          Sarah
cand_3          Nigel

所以我正在寻找的结果将类似于：

Candidate       Votes
Dave            6
Sarah           7
Nigel           5

SELECT
    cn.cand_name, 
    count(cv1.vote_1) * 3 as vote_1, 
    count(cv2.vote_2) * 2 as vote_2, 
    count(cv3.vote_3) as vote_3
FROM
    candidate_names cn
    LEFT JOIN
    candidate_votes cv1 ON cv1.vote_1 = cn.cand_number
    LEFT JOIN
    candidate_votes cv2 ON cv2.vote_2 = cn.cand_number
    LEFT JOIN
    candidate_votes cv3 ON cv3.vote_3 = cn.cand_number
GROUP BY cn.cand_name;

这也允许您添加所有投票

(count(cv1.vote_1) * 3) +
    (count(cv2.vote_2) * 2) +
    count(cv3.vote_3) as totalvotes

编辑：行被 JOIN 相乘，这就是 cand2 和 cand3 错误的原因

SELECT
    cn.cand_name, 
    SUM(CASE WHEN cv.vote_1 = cn.cand_number THEN 3 ELSE 0 END) as vote_1, 
    SUM(CASE WHEN cv.vote_2 = cn.cand_number THEN 2 ELSE 0 END) as vote_2, 
    SUM(CASE WHEN cv.vote_3 = cn.cand_number THEN 1 ELSE 0 END) as vote_3
FROM
    candidate_names cn
    JOIN
    candidate_votes cv ON cn.cand_number IN (cv.vote_1, cv.vote_2, cv.vote_3)
GROUP BY cn.cand_name;