A ListView
在我的应用程序中有许多字符串元素,例如name
, experience
, date of joining
等等我只是想做name
大胆的。所有字符串元素都将位于一个TextView
.
my XML
:
<ImageView
android:id="@+id/logo"
android:layout_width="55dp"
android:layout_height="55dp"
android:layout_marginLeft="5dp"
android:layout_marginRight="5dp"
android:layout_marginTop="15dp" >
</ImageView>
<TextView
android:id="@+id/label"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_toRightOf="@id/logo"
android:padding="5dp"
android:textSize="12dp" >
</TextView>
我设置 ListView 项的 TextView 的代码:
holder.text.setText(name + "\n" + expirience + " " + dateOfJoininf);
假设你有一个TextView
called etx
。然后您将使用以下代码:
final SpannableStringBuilder sb = new SpannableStringBuilder("HELLOO");
final StyleSpan bss = new StyleSpan(android.graphics.Typeface.BOLD); // Span to make text bold
final StyleSpan iss = new StyleSpan(android.graphics.Typeface.ITALIC); //Span to make text italic
sb.setSpan(bss, 0, 4, Spannable.SPAN_INCLUSIVE_INCLUSIVE); // make first 4 characters Bold
sb.setSpan(iss, 4, 6, Spannable.SPAN_INCLUSIVE_INCLUSIVE); // make last 2 characters Italic
etx.setText(sb);
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