如何避免代码重复

我有以下代码，我想以最少代码行的方式编写它，并且工作以相同的方式完成。我怎样才能做到这一点？

List<Category> categoryList = new List<Category>();
categoryList = Category.LoadForProject(project.ID).ToList();
List<string> categories = new List<string>(Categories);
IList<Category> currentCategories = Category.LoadForProject(project.ID).ToList();
if (currentCategories != null)
{
    foreach (var existingCategories in currentCategories)
    {
        if (categories.Contains(existingCategories.Name))
           categories.Remove(existingCategories.Name);
        else
            existingCategories.Delete(Services.UserServices.User);
    }
    foreach (string item in categories)
    {
        Category category = new Category(project, item.ToString());
        category.Project = project;
        category.Save();
   }
}

List<string> priorities = new List<string>(Priorities);
IList<Priority> currentPriorities = Priority.LoadForProject(project.ID).ToList();
if (currentPriorities != null)
{
   foreach (var existingPriorities in currentPriorities)
   {
       if (priorities.Contains(existingPriorities.Name))
           priorities.Remove(existingPriorities.Name);
       else
           existingPriorities.Delete(Services.UserServices.User);
   }
   foreach (string item in priorities)
   {
       Priority priority = new Priority(project, item.ToString());
       priority.Project = project;
       priority.Save();
   }
}

像这样的事情应该这样做：

public IList<T> DoYourThing<T>(IList<T> items, IList<T> currentItems, Project project) where T : CommonBaseType
{
  if (currentItems != null)
  {
    foreach (var existingItem in currentItems)
    {
      if (items.Contains(existingItem.Name))
        items.Remove(existingItem.Name);
      else
        existingItems.Delete(Services.UserServices.User);
    }
    foreach (string item in items)
    {
      T newItem = Activator.CreateInstance(typeof(T), new object[] {project, item.ToString()}) as T;
      newItem.Project = project;
      newItem.Save();
    }
  }

  return currentItems;
}

然后你可以这样调用它：

var currentCategories = DoYourThing(Categories.ToList(), Category.LoadForProject(project.ID).ToList());
var currentProjects = DoYourThing(Priorities.ToList(), Priority.LoadForProject(project.ID).ToList());

最后，有两点需要特别注意： 首先，函数有一个通用条件where T : CommonBaseType。我假设类别和项目有一个共同的基本类型或接口，其中包括名称。如果没有，您应该摆脱该条件并使用 Dynamic 来获取 Name。

其次，我使用 Activator.Create 为您创建该类。这是一个棘手的部分，如果你不知道这个技巧，就很难弄清楚

祝你好运！