我无法将信息从表单输入到数据库[关闭]

“我正在尝试从注册表中将数据输入数据库，但它似乎不起作用，我认为我做了正确的编码，我不确定我在哪里做错了，我逐个代码读取代码，并且我创建的所有数据库都遵循了。

<form method='post' action='login.php'>
<table width='400' border='5' align='CENTER'>

<tr>
<td><h1>Registration</h1></td>

</tr>

<tr>
<td>User Name:</td>
<td><input type='text' name='name'/></td>
</tr>

<tr>
<td>Password:</td>
<td><input type='password' name='pass'/></td>
</tr>
<tr>
<td>Email:</td>
<td><input type='text' name='email'/></td>
</tr>
<tr>
<td><input type='submit' name='register' value='register'/></td>

</tr>

</table>
</form>

<?php
    $connect=mysql_connect("localhost","root","");
    $db_selected = mysql_select_db("users_db", $connect); 
    if(isset($_POST['submit'])){

    $users_name = $_POST['name'];
    $users_pass = $_POST['pass'];
    $users_email = $_POST['email'];

    if($users_name==''){
    echo "<script>alert('Please enter your Username')</script>";
        exit();
    }

    if($users_pass==''){
    echo "<script>alert('Please enter your password')</script>";
        exit();
    }

    if($users_email==''){
    echo "<script>alert('Please enter your email')</script>";
        exit();
    }

    $check_email="select*from 
    users where 
    users_email='$users_email'";

    $run = 
    mysql_query($check_email) or
    die(mysql_error());


    if(mysql_num_rows($run)>0){

    echo"<script>alert('Email $users_email 
    is already exist in our databse, please try another 
    one')</script>";  exit();
    }


    $query = "insert into users 
    (users_name,users_pass,users_email) values('
    $users_name','$users_pass','$users_email')";


    { 
        $result = mysql_query($query) 
        or die(mysql_error());
    }

    echo"<script>alert
    window.open('','_self')</script>";
    }

?>

将初始分配更改为：

$users_name = mysql_real_escape_string($_POST['name']);
$users_pass = mysql_real_escape_string($_POST['pass']);
$users_email = mysql_real_escape_string($_POST['email']);

以避免字段中的特殊字符出现问题，并防止 SQL 注入。

将插入查询更改为：

$query = "insert into users (users_name,users_pass,users_email)
          values('$users_name','$users_pass','$users_email')";

你之前有一个无关的换行符和空格$users_name，因此这些被插入到数据库中。