如果您花时间发布格式正确的 JSON 和 XML,那就太好了,但无论如何。我关注的是这里的难题,即将重复的 XML 元素映射到 JSON,如果将以下内容粘贴到Scenario
你可以看到它的工作原理:
* def json =
"""
{
"Main": {
"Cd":"ABC",
"descriptionTxt":"Sample Main",
"type":"A",
"codeType":"P",
"dt":"2018-10-15T00:00:00-05:00",
"validity":"3",
"segment":"Personal"
},
"testList":[
{
"code":"123",
"descriptionTxt":"My Description",
"categoryCd":"DUDU"
},
{
"code":"675",
"descriptionTxt":"His Description"
},
{
"code":"345",
"descriptionTxt":"Your Description",
"categoryCd":"BH"
}
]
}
"""
* def xml =
"""
<ns4:root xmlns:ns4="http://foo.com" xmlns:ns5="http://bar.com">
<ns4:Test>
<ns5:code>123</ns5:code>
<ns5:description>My Description</ns5:description>
<ns5:categoryCode>DUDU</ns5:categoryCode>
<ns5:unwanted>Unwanted XML Parameter</ns5:unwanted>
</ns4:Test>
<ns4:Test>
<ns5:code>345</ns5:code>
<ns5:description>Your Description</ns5:description>
<ns5:categoryCode>BH</ns5:categoryCode>
</ns4:Test>
<ns4:Test>
<ns5:code>675</ns5:code>
<ns5:description>His Description</ns5:description>
<ns5:unwanted>Unwanted XML Parameter</ns5:unwanted>
</ns4:Test>
</ns4:root>
"""
* def list = $xml/root/Test
* def xpath = function(x, p){ try { return karate.xmlPath(x, p) } catch (e) { return '#notpresent' } }
* def fun = function(x){ return { code: xpath(x, '/Test/code'), descriptionTxt: xpath(x, '/Test/description'), categoryCd: xpath(x, '/Test/categoryCode') } }
* def temp = karate.map(list, fun)
* print temp
* print json.testList
* match json.testList contains temp
映射 JSON 的其余部分对您来说是一项练习。请参阅文档。另请参阅此答案以获取更多想法:空手道 - 匹配两个动态响应 https://stackoverflow.com/q/53118601/143475