Django 基于类的视图 (TemplateView) 中的 URL 参数和逻辑

我不清楚如何最好地访问 Django 1.5 中基于类的视图中的 URL 参数。

考虑以下：

View:

from django.views.generic.base import TemplateView


class Yearly(TemplateView):
    template_name = "calendars/yearly.html"

    current_year = datetime.datetime.now().year
    current_month = datetime.datetime.now().month

    def get_context_data(self, **kwargs):
        context = super(Yearly, self).get_context_data(**kwargs)
        context['current_year'] = self.current_year
        context['current_month'] = self.current_month
        return context

URLCONF:

from .views import Yearly


urlpatterns = patterns('',
    url(
        regex=r'^(?P<year>\d+)/$',
        view=Yearly.as_view(),
        name='yearly-view'
    ),
)

我想访问year在我看来，参数，所以我可以执行如下逻辑：

month_names = [
    "January", "February", "March", "April", 
    "May", "June", "July", "August", 
    "September", "October", "November", "December"
]

for month, month_name in enumerate(month_names, start=1):
    is_current = False
    if year == current_year and month == current_month:
        is_current = True
        months.append({
            'month': month,
            'name': month_name,
            'is_current': is_current
        })

如何最好地访问 CBV 中的 url 参数（如上面的子类）TemplateView理想情况下应该将这样的逻辑放置在哪里，例如。在一个方法中？

要访问基于类的视图中的 url 参数，请使用self.args or self.kwargs所以你可以通过这样做来访问它self.kwargs['year']