我个人有使用 Jersey 实现 REST in java (JAX-RS) 的经验。然后我通过 Android 应用程序连接到这个 RESTful Web 服务。
在您的 Android 应用程序中，您可以使用 HTTP 客户端库。它支持HTTP命令，如POST、PUT、DELETE、GET。例如使用 GET 命令并以 JSON 格式或 TextPlain 传输数据：
public class Client {
private String server;
public Client(String server) {
this.server = server;
}
private String getBase() {
return server;
}
public String getBaseURI(String str) {
String result = "";
try {
HttpParams httpParameters = new BasicHttpParams();
int timeoutConnection = 3000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
int timeoutSocket = 5000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
HttpGet getRequest = new HttpGet(getBase() + str);
getRequest.addHeader("accept", "application/json");
HttpResponse response = httpClient.execute(getRequest);
result = getResult(response).toString();
httpClient.getConnectionManager().shutdown();
} catch (Exception e) {
System.out.println(e.getMessage());
}
return result;
}
public String getBaseURIText(String str) {
String result = "";
try {
HttpParams httpParameters = new BasicHttpParams();
int timeoutConnection = 3000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
int timeoutSocket = 5000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
HttpGet getRequest = new HttpGet(getBase() + str);
getRequest.addHeader("accept", "text/plain");
HttpResponse response = httpClient.execute(getRequest);
result = getResult(response).toString();
httpClient.getConnectionManager().shutdown();
} catch (Exception e) {
System.out.println(e.getMessage());
}
return result;
}
private StringBuilder getResult(HttpResponse response) throws IllegalStateException, IOException {
StringBuilder result = new StringBuilder();
BufferedReader br = new BufferedReader(new InputStreamReader((response.getEntity().getContent())), 1024);
String output;
while ((output = br.readLine()) != null)
result.append(output);
return result;
}
}
然后在 android 类中你可以：
Client client = new Client("http://localhost:6577/Example/rest/");
String str = client.getBaseURI("Example"); // Json format
解析 JSON 字符串（或者可能是 xml）并在 ListView、GridView 等中使用它
我简单浏览了一下您提供的链接。那里有一个很好的观点。对于 API 级别 11 或更高级别，您需要在单独的线程上实现网络连接。看看这个链接：Android 中的 HTTP 客户端 API 级别 11 或更高级别.
这是我在 Client 类中使用 HTTP 发布对象的方式：
public String postBaseURI(String str, String strUrl) {
String result = "";
try {
HttpParams httpParameters = new BasicHttpParams();
int timeoutConnection = 3000;
HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
int timeoutSocket = 5000;
HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters);
HttpPost postRequest = new HttpPost(getBase() + strUrl);
StringEntity input = new StringEntity(str);
input.setContentType("application/json");
postRequest.setEntity(input);
HttpResponse response = httpClient.execute(postRequest);
result = getResult(response).toString();
httpClient.getConnectionManager().shutdown();
} catch (Exception e) {
System.out.println(e.getMessage());
}
return result;
}
在 REST WS 中，我将对象发布到数据库：
@POST
@Path("/post")
@Consumes(MediaType.APPLICATION_JSON)
@Produces(MediaType.TEXT_PLAIN)
public Response addTask(Task task) {
Session session = HibernateUtil.getSessionFactory().getCurrentSession();
session.beginTransaction();
session.save(task);
session.getTransaction().commit();
return Response.status(Response.Status.CREATED).build();
}
