我正在开发一个使用 GPS 坐标作为排行榜的 iPhone 应用程序。我不需要精确的坐标——实际上我不需要曾经想要坐标要准确,以保护用户隐私。
我为desiredAccuracy指定了kCLLocationAccuracyThreeKilometers,但是当GPS处于活动状态时,它似乎也可以在设备拥有它时获取确切的位置。
问题:是否有任何简单的算法可以用来使 GPS 数据更加粗糙?比如说,将其细化到 3 公里。
如果我只是按比例放大数字并删除小数点,然后再次按比例缩小,那么世界上某些地方的数据会比其他地方更粗糙。
Thanks!
虽然马克上面的答案很有用,但它仍然没有产生具有一致结果的公式,因为它依赖于随机数生成器。
我的朋友对此给出了最佳答案:
根据粒度将纬度、经度四舍五入到最接近的有效数字,但这会导致某个位置附近的所有纬度/经度最终出现在同一位置。此方法将使用纬度/经度中两点之间的距离来计算经度的舍入。使用下面相同的公式并将路线设置为0,那么距离就是您的距离粒度。计算所得的新纬度/经度减去两个纬度/经度即可得到纬度的舍入量。然后将航向设置为 90 并重新计算并从旧的纬度/经度中减去新的纬度/经度以获得经度的舍入量。
这是 C++ 代码:
class LocationUtility
{
public: static Location getLocationNow()
{
Location location;
if(context != null)
{
double latitude = 0;
double longitude = 0;
::of_getCurrentLocation(&latitude, &longitude);
location.setLatitude(latitude);
location.setLongitude(longitude);
location = makeLocationCoarse(location);
}
return location;
}
public: static Location makeLocationCoarse(const Location& location)
{
double granularityInMeters = 3 * 1000;
return makeLocationCoarse(location, granularityInMeters);
}
public: static Location makeLocationCoarse(const Location& location,
double granularityInMeters)
{
Location courseLocation;
if(location.getLatitude() == (double)0 &&
location.getLongitude() == (double)0)
{
// Special marker, don't bother.
}
else
{
double granularityLat = 0;
double granularityLon = 0;
{
// Calculate granularityLat
{
double angleUpInRadians = 0;
Location newLocationUp = getLocationOffsetBy(location,
granularityInMeters, angleUpInRadians);
granularityLat = location.getLatitude() -
newLocationUp.getLatitude();
if(granularityLat < (double)0)
{
granularityLat = -granularityLat;
}
}
// Calculate granularityLon
{
double angleRightInRadians = 1.57079633;
Location newLocationRight = getLocationOffsetBy(location,
granularityInMeters, angleRightInRadians);
granularityLon = location.getLongitude() -
newLocationRight.getLongitude();
if(granularityLon < (double)0)
{
granularityLon = -granularityLon;
}
}
}
double courseLatitude = location.getLatitude();
double courseLongitude = location.getLongitude();
{
if(granularityLon == (double)0 || granularityLat == (double)0)
{
courseLatitude = 0;
courseLongitude = 0;
}
else
{
courseLatitude = (int)(courseLatitude / granularityLat) *
granularityLat;
courseLongitude = (int)(courseLongitude / granularityLon) *
granularityLon;
}
}
courseLocation.setLatitude(courseLatitude);
courseLocation.setLongitude(courseLongitude);
}
return courseLocation;
}
// http://www.movable-type.co.uk/scripts/latlong.html
private: static Location getLocationOffsetBy(const Location& location,
double offsetInMeters, double angleInRadians)
{
Location newLocation;
double lat1 = location.getLatitude();
double lon1 = location.getLongitude();
lat1 = deg2rad(lat1);
lon1 = deg2rad(lon1);
double distanceKm = offsetInMeters / (double)1000;
const double earthRadiusKm = 6371;
double lat2 = asin( sin(lat1)*cos(distanceKm/earthRadiusKm) +
cos(lat1)*sin(distanceKm/earthRadiusKm)*cos(angleInRadians) );
double lon2 = lon1 +
atan2(sin(angleInRadians)*sin(distanceKm/earthRadiusKm)*cos(lat1),
cos(distanceKm/earthRadiusKm)-sin(lat1)*sin(lat2));
lat2 = rad2deg(lat2);
lon2 = rad2deg(lon2);
newLocation.setLatitude(lat2);
newLocation.setLongitude(lon2);
return newLocation;
}
private: static double rad2deg(double radians)
{
static double ratio = (double)(180.0 / 3.141592653589793238);
return radians * ratio;
}
private: static double deg2rad(double radians)
{
static double ratio = (double)(180.0 / 3.141592653589793238);
return radians / ratio;
}
/*
public: static void testCoarse()
{
Location vancouver(49.2445, -123.099146);
Location vancouver2 = makeLocationCoarse(vancouver);
Location korea(37.423938, 126.692488);
Location korea2 = makeLocationCoarse(korea);
Location hiroshima(34.3937, 132.464);
Location hiroshima2 = makeLocationCoarse(hiroshima);
Location zagreb(45.791958, 15.935786);
Location zagreb2 = makeLocationCoarse(zagreb);
Location anchorage(61.367778, -149.900208);
Location anchorage2 = makeLocationCoarse(anchorage);
}*/
};
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