我有一个包含数字和数学运算符的字符串（+,x,-, /) 混入其中
'12+345x6/789'
我需要将其转换为由这些数学运算符分隔的数组。
[12, +, 345, x, 6, /, 789]
执行此操作的简单方法是什么？
连续分割非数字 chars \D+ you get
console.log ('12+345x6/789'.split (/\D+/))
// [ '12', '345', '6', '789' ]
如果您添加一个捕获组, (\D+)你也得到了分隔符
console.log ('12+345x6/789'.split (/(\D+)/))
// [ "12", "+", "345", "x", "6", "/", "789" ]
如果您想支持解析小数，请将正则表达式更改为/([^0-9.]+)/- 笔记，\D上面使用的等价于[^0-9]，所以我们在这里所做的就是添加.到字符类
console.log ('12+3.4x5'.split (/([^0-9.]+)/))
// [ "12", "+", "3.4", "x", "5" ]
以及编写程序其余部分的可能方法
const cont = x =>
k => k (x)
const infix = f => x =>
cont (f (x))
const apply = x => f =>
cont (f (x))
const identity = x =>
x
const empty =
Symbol ()
const evaluate = ([ token = empty, ...rest], then = cont (identity)) => {
if (token === empty) {
return then
}
else {
switch (token) {
case "+":
return evaluate (rest, then (infix (x => y => x + y)))
case "x":
return evaluate (rest, then (infix (x => y => x * y)))
case "/":
return evaluate (rest, then (infix (x => y => x / y >> 0)))
default:
return evaluate (rest, then (apply (Number (token))))
}
}
}
const parse = program =>
program.split (/(\D+)/)
const exec = program =>
evaluate (parse (program)) (console.log)
exec ('') // 0
exec ('1') // 1
exec ('1+2') // 3
exec ('1+2+3') // 6
exec ('1+2+3x4') // 24
exec ('1+2+3x4/2') // 12
exec ('12+345x6/789') // 2
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