我需要以这种格式获取一组 github 的日期和提交结果:
Date Commit
19 Mar 2015 b6959eafe0df6031485509c539e22eaf2780919c
1 Apr 2015 9a1f13339cc7d43930440c2350ea3060b72c8503
1 Apr 2015 1e76036421ca4d72c371182fc494af514911b099
我可以使用以下命令获取日期:
git log | grep Date: | awk '{print $4 " " $3 " " $6}'
和提交
git log | grep commit | awk '{print $2}'
如何组合命令,以便在同一行中打印两个结果?
这是 git 日志的示例:
commit 1e76036421ca4d72c371182fc494af514911b099
Author: xxxx
Date: Wed Apr 1 17:35:36 2015 +0200
First web app commit
First web app commit
commit 9a1f13339cc7d43930440c2350ea3060b72c8503
Author: xxxx
Date: Wed Apr 1 17:28:42 2015 +0200
change from app to website
commit b6959eafe0df6031485509c539e22eaf2780919c
Author: xxx
Date: Thu Mar 19 18:58:33 2015 +0100
First remote commit: hello world
scheleton of the project now available
commit a41d419de46a59e72dbc52e5f39c9d8a8a9af72a
Author: xxxx
Date: Thu Mar 19 17:31:16 2015 +0100
Initial commit
“git log”命令功能强大,足以自行处理此问题。尝试一下这个的变体:
git log --date=iso --pretty=format:"date={%ad}, commit={%H}"
对我来说这个输出:
date={2014-12-12 14:14:23 -0800}, commit={75390af8bcd42c4dde6d841dc53f66a9ca91f460}
date={2014-12-09 18:53:32 -0800}, commit={8dcf9eb10611e6ac778e518cf37efb041c69f5b5}
date={2014-12-11 17:17:26 -0800}, commit={c3c1120b6dda6b317e1de5c7fe4eed7c8741ea1a}
要实现您指定的确切格式(尽管日期格式更合理一些),请尝试以下操作:
git log --date=short --pretty=format:"%ad %H"
输出如下:
2015-08-18 1d0ca5a596f02958c4ba8ff269def3f235c64495
2015-08-18 d92fc3ebb62d2ca3e24322db2b669fdaebde7ea1
2015-08-18 6ba3970620e19699c2969b1eed5c479b07b8908a
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