NSPredicate 精确匹配

 NSArray *arrData = [NSArray arrayWithObjects:
                    @"cloud,country,plant",
                    @"country,cloud,plant",
                    @"country,plant,cloud",
                    @"clouds,country,plant"
                    ,@"country,clouds,plant",
                    nil];

从上面的 NSArray 中，我想要带有单词“cloud”的对象

我尝试了下面的代码

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"(self beginswith %@ OR self contains[CD] %@)",@"cloud",@",cloud"];
NSArray *arrResult = [arrData filteredArrayUsingPredicate:predicate];

但它给出了 arrResult 中的所有 5 个对象。但我只需要 3 (0,1,2) 个对象。

Try:

 NSPredicate* predicate = [NSPredicate predicateWithBlock:^(NSString* string, NSDictionary* options){

    NSArray* array = [string componentsSeparatedByString:@","];

    return [array containsObject:@"cloud"];

}];