如何求多边形的垂直距离？

我现在有 n 个坐标，从中创建了一个多边形，如果该多边形中有一个坐标，那么如何找到点和多边形的垂直距离？

coords = [(45.888106581826065, 8.512891340789281), (45.89087605100282, 8.51131888355673), (45.89242907135495, 8.51043574866833), (45.88810733356788, 8.512894063368899), (45.890876868519385, 8.51132182341189), (45.892063379278696, 8.510647148893547), (45.89243094789967, 8.510442653438174), (45.88811958097381, 8.512938419782168), (45.89088904461223, 8.51136560966078), (45.89207575921023, 8.510692030810025), (45.89244290698806, 8.51048665710127), (45.88813186579548, 8.512982911786311), (45.89090145183551, 8.511410227156235), (45.89245416375836, 8.510528076647585), (45.88813271861146, 8.512986000437545), (45.89090242476677, 8.511413725908412), (45.89245495631277, 8.510530992872562)]

需要检查的点是否在多边形中：

p2 = Point(45.88831, 8.51283)

检查坐标是否(p2) 是否在多边形内：

poly = MultiPoint(coords).convex_hull
    if p2.within(poly):
        print("Givien point is in polygon")

我尝试使用boundary.distance函数来查找距离，我得到的结果为4.7144012366024但不确定是垂直距离还是其他什么！

print(poly.boundary.distance(p2))
#output: 4.71440123660249

谁能帮我求出该点的垂直距离？

对于每个多边形边AB进行点投影C onto AB使用向量的点积并得到它的长度：

t = (AB.dot.AC) / (AB.dot.AB)  ## ratio of  AP / AB
L = length(t*AB - AC)  ## CP distance at the picture

请注意，对于t外部参数0..1射程投影取决于AB

Example:

import math
def proj(x1,y1,x2,y2,cx,cy):
    dx = x2 - x1
    dy = y2 - y1
    cdx = cx - x1
    cdy = cy - y1
    t = (cdx * dx + cdy * dy) / (dx * dx + dy * dy)
    if t < 0 or t > 1:
        print("Projection lies outside segment")
    px = x1 + t * dx
    py = y1 + t * dy
    print("Projection coordinates: %5.1f %5.1f" % (px, py))
    nlen = math.hypot(t * dx - cdx, t * dy - cdy)
    print("Distance from point to line: %5.1f" % nlen)
    alonglen = math.hypot(t * dx, t * dy)
    print("Along segment distance:  %5.1f" % alonglen)

proj(0, 0, 4, 16/3, 0, 5)

>>
Projection coordinates:   2.4   3.2
Distance from point to line:   3.0
Along segment distance:    4.0