如何将两个嵌套字典合并到同一字典下

例如我有一本字典：

dictA={"nest1":{"01feb":[1,2,3,4,5],"02feb":[1,7,8,9,10]},
       "nest2":{"01feb":[1,2,3,4,5],"02feb":[6,4,8,10,10]}}

里面的列表具有相同的长度。我需要合并nest1 and nest2作为一本字典，结果应该是这样的：

dictA={"nest":{"01feb":[2,4,6,8,10],"02feb":[7,11,16,19,20]}}

您可以使用dict comprehension, map() and zip()就像这个例子（适用于 Python 2 和 Python 3）。

dictA = {'nest1': {'01feb': [1, 2, 3, 4, 5], '02feb': [1, 7, 8, 9, 10]},
 'nest2': {'01feb': [1, 2, 3, 4, 5], '02feb': [6, 4, 8, 10, 10]}}

a = (v.items() for _, v in map(list, dictA.items()))
# You can also use another map():
# final = {'nest': {k: list(map(sum, zip(v,j))) for (k, v), (_, j) in zip(*a)}}
final = {'nest': {k: [m+n for m, n in zip(v, j)] for (k, v), (_, j) in zip(*a)}}

print(final)

Output:

{'nest': {'02feb': [7, 11, 16, 19, 20], '01feb': [2, 4, 6, 8, 10]}}