这个问题的最佳答案描述了一种在 Java 中实现高效 XSLT 管道的技术:
Java 中的高效 XSLT 管道(或将结果重定向到源)
不幸的是,虽然 Transformer 似乎公开了一个用于设置 XSLT 参数的 API,但这似乎没有任何效果。例如,我有以下代码:
变压器.java
import javax.xml.transform.sax.SAXTransformerFactory;
import javax.xml.transform.Templates;
import javax.xml.transform.sax.TransformerHandler;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import javax.xml.transform.sax.SAXResult;
import javax.xml.transform.Transformer;
import java.io.File;
public class MyTransformer {
public static void main(String[] args) throws javax.xml.transform.TransformerConfigurationException, javax.xml.transform.TransformerException{
SAXTransformerFactory stf = (SAXTransformerFactory)TransformerFactory.newInstance();
// These templates objects could be reused and obtained from elsewhere.
Templates templates1 = stf.newTemplates(new StreamSource( new File("MyStylesheet1.xslt")));
Templates templates2 = stf.newTemplates(new StreamSource(new File("MyStylesheet2.xslt")));
TransformerHandler th1 = stf.newTransformerHandler(templates1);
TransformerHandler th2 = stf.newTransformerHandler(templates2);
th1.setResult(new SAXResult(th2));
th2.setResult(new StreamResult(System.out));
Transformer t = stf.newTransformer();
//SETTING PARAMETERS HERE
t.setParameter("foo","this is from param 1");
t.setParameter("bar","this is from param 2");
t.transform(new StreamSource(new File("in.xml")), new SAXResult(th1));
// th1 feeds th2, which in turn feeds System.out.
}
}
MyStylesheet1.xslt
<?xml version="1.0"?>
<stylesheet xmlns="http://www.w3.org/1999/XSL/Transform" xmlns:foo="urn:foo" version="1.0">
<output method="xml"/>
<param name="foo"/>
<template match="@*|node()">
<copy>
<apply-templates select="@*|node()"/>
</copy>
</template>
<template match="foo:my/foo:hello">
<copy>
<foo:world>
foo is : <value-of select="$foo"/>
</foo:world>
</copy>
</template>
</stylesheet>
MyStylesheet2.xslt
<?xml version="1.0"?>
<stylesheet xmlns="http://www.w3.org/1999/XSL/Transform" xmlns:foo="urn:foo" version="1.0">
<output method="xml"/>
<param name="bar"/>
<template match="@*|node()">
<copy>
<apply-templates select="@*|node()"/>
</copy>
</template>
<template match="foo:my/foo:hello/foo:world">
<copy>
<apply-templates select="@*|node()"/>
<attribute name="attr">
<value-of select="$bar"/>
</attribute>
</copy>
</template>
</stylesheet>
in.xml
<my xmlns="urn:foo">
<hello/>
</my>
这给了我以下输出:
<?xml version="1.0" encoding="UTF-8"?><my xmlns="urn:foo">
<hello><foo:world xmlns:foo="urn:foo">foo is : </foo:world></hello>
</my>
正如你所看到的 foo:world/@attr 是空的,并且 foo:world 的文本内容是“foo is:”。预期的行为是它们应该使用传递到 setParameter 方法的参数进行填充。
有没有办法使用此技术设置 XSL 转换参数。如果没有,有人可以推荐一种替代技术来在 Java 中有效地转换样式表,这样也可以设置 XSLT 参数吗?