如何使用 beautifulsoup 打印 href 属性，同时通过 selenium 实现自动化？

蓝色元素的 href 值是我想从此 HTML 访问的内容

我尝试了几种方法来打印链接，但没有成功。

我的代码如下：-

discover_page = BeautifulSoup(r.text, 'html.parser')

finding_accounts = discover_page.find_all("a", class_="author track")
print(len(finding_accounts))

finding_accounts = discover_page.find_all('a[class="author track"]')
print(len(finding_accounts))

accounts = discover_page.select('a', {'class': 'author track'})['href']
print(len(accounts))

Output:- 
0
0
TypeError: 'dict' object is not callable

网页的网址是https://society6.com/discover但网址更改为https://society6.com/society?show=2登录我的帐户后

我在这里做错了什么？

注意：-我在这里使用 selenium chrome 浏览器。这里给出的答案在我的终端中有效，但在我运行文件时无效

我的完整代码：-

from selenium import webdriver
import time
import requests
from bs4 import BeautifulSoup
import lxml

driver = webdriver.Chrome()
driver.get("https://society6.com/login?done=/")
username = driver.find_element_by_id('email')
username.send_keys("[email protected]")
password = driver.find_element_by_id('password')
password.send_keys("sultan1997")
driver.find_element_by_name('login').click()

time.sleep(5)

driver.find_element_by_link_text('My Society').click()
driver.find_element_by_link_text('Discover').click()

time.sleep(5)

r = requests.get(driver.current_url)
r.raise_for_status()

'''discover_page = BeautifulSoup(r.html.raw_html, 'html.parser')

finding_accounts = discover_page.find_all("a", class_="author track")
print(len(finding_accounts))

finding_accounts = discover_page.find_all('a[class="author track"]')
print(len(finding_accounts))


links = []
for a in discover_page.find_all('a', class_ = 'author track'): 
        links.append(a['href'])
        #links.append(a.get('href'))

print(links)'''

#discover_page.find_all('a')

links = []
for a in discover_page.find_all("a", attrs = {"class": "author track"}): 
        links.append(a['href'])
        #links.append(a.get('href'))

print(links)

#soup.find_all("a", attrs = {"class": "author track"})'''

soup = BeautifulSoup(r.content, "lxml")
a_tags = soup.find_all("a", attrs={"class": "author track"})

for a in soup.find_all('a',{'class':'author track'}):
    print('https://society6.com'+a['href'])

文档中的代码是我正在尝试使用的代码

如果您希望找到所有链接而不需要在 Beautifulsoup 中手动尝试。然后去请求-html

获取所有链接的示例代码，

from requests_html import HTMLSession
from bs4 import BeautifulSoup

url = 'https://society6.com/discover'
session = HTMLSession(mock_browser=True)
r = session.get(url, headers={'User-Agent': 'Mozilla/5.0'})

print(r.html.links)
print(r.html.absolute_links)

soup = BeautifulSoup(r.html.raw_html, 'html.parser')
a_tags = soup.find_all("a", attrs={"class": "author track"})
for a_tag in a_tags:
    print(a_tag['href'])