如果我睡10毫秒。我需要增加什么才能获得第二个？

即我正在使用std::this_thread::sleep_for(std::chrono::milliseconds(10));在程序循环中。

如果我有一个变量在此循环中递增以显示经过的秒数，我需要递增什么？

i.e. float x = 0;

对于每个步骤：

x += 0.01

我尝试过 0.1、0.01、0.001，但它们看起来要么太快要么太慢。

我建议使用absolute时间点和wait_until()。像这样的东西：

// steady_clock is more reliable than high_resolution_clock
auto const start_time = std::chrono::steady_clock::now();
auto const wait_time = std::chrono::milliseconds{10};
auto next_time = start_time + wait_time; // regularly updated time point

for(;;)
{
    // wait for next absolute time point
    std::this_thread::sleep_until(next_time);
    next_time += wait_time; // increment absolute time

    // Use milliseconds to get to seconds to avoid
    // rounding to the nearest second
    auto const total_time = std::chrono::steady_clock::now() - start_time;
    auto const total_millisecs = double(std::chrono::duration_cast<std::chrono::milliseconds>(total_time).count());
    auto const total_seconds = total_millisecs / 1000.0;

    std::cout << "seconds: " << total_seconds << '\n';
}