我想从 nsmutablearray 中删除重复项。
数组结构:-
(
{
"act_end_date" = "";
"act_entry_date" = "13/11/2014";
"act_recurrrance_type" = Daily;
"act_start_date" = "2014-11-13";
"row_id" = 0;
"act_id" = 2;
}
{
"act_end_date" = "";
"act_entry_date" = "13/11/2014";
"act_recurrrance_type" = Daily;
"act_start_date" = "2014-11-13";
"row_id" = 1;
"act_id" = 2;
}
{
"act_end_date" = "";
"act_entry_date" = "16/11/2014";
"act_recurrrance_type" = Daily1;
"act_start_date" = "2014-11-15";
"row_id" = 2;
"act_id" = 3;
}
)
我想要的是检查数组中包含具有相同 act_id 的任何字典的位置。
如果是,则删除第一个字典。
即上述数组的预期结果是:-
(
{
"act_end_date" = "";
"act_entry_date" = "13/11/2014";
"act_recurrrance_type" = Daily;
"act_start_date" = "2014-11-13";
"row_id" = 1;
"act_id" = 2;
}
{
"act_end_date" = "";
"act_entry_date" = "16/11/2014";
"act_recurrrance_type" = Daily1;
"act_start_date" = "2014-11-15";
"row_id" = 2;
"act_id" = 3;
}
)
他们有什么办法吗?
使用 NSPREDICATE 可以吗?
我尝试通过以下方式做到这一点:-
NSMutableArray *filteredArray = [NSMutableArray array];
for (NSMutableDictionary* E1 in Event_Array)
{
BOOL hasDuplicate = [[filteredArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"act_id == %@", [E1 objectForKey:@"act_id"]]] count] > 0;
if (!hasDuplicate)
{
[filteredArray addObject:E1];
}
}
因为它返回数组:---
(
{
"act_end_date" = "";
"act_entry_date" = "13/11/2014";
"act_recurrrance_type" = Daily;
"act_start_date" = "2014-11-13";
"row_id" = 0;
"act_id" = 2;
}
)
我想要的是
(
{
"act_end_date" = "";
"act_entry_date" = "13/11/2014";
"act_recurrrance_type" = Daily;
"act_start_date" = "2014-11-13";
"row_id" = 1;
"act_id" = 2;
}
)