我的代码不太长，所以我将其全部粘贴到这里。
代码不完整，但当我运行它时，它首先跳转到它应该的情况“开始”，然后跳转到情况“结束”。我可以看到它，因为它打印了两个块的控制台日志文本。为什么会跳到“结束”案例？
<html>
<body>
<script>
function stepStream(stream,step){
switch (stream[step]){
case "start":
console.log("Started reading stream...");
case "end":
var success = "Finished reading dataStream.";
console.log(success);
return success;
default:
throw "Data stream format is bad";
case "gesture":
console.log("Running case gesture! But why?");
step+=1;
stepStream(stream,step);
case "say":
step+=1;
stepStream(stream,step);
case "sleep":
step+=1;
stepStream(stream,step);
}
}
var sentence1 = "Where are my bananas? I thought you put them in my bag?";
var sentence2 = "This is a rather irritating situattion.";
var dataStream = ["start","gesture","banzai","sleep",1.0,"say",sentence1,
"say",sentence2,"gesture","kubikasige","end"];
stepStream(dataStream,0);//Second parameter sets where to start reading the dataStream.
</script>
</body>
</html>
问题是你错过了break您之后的关键字case代码。如果没有break，后续的块将会被执行，这就是为什么end之后执行start代码。您可以阅读有关此内容的更多信息这个 W3Schools 链接.
此外，从JS参考:
与每个 case 标签关联的可选的break语句确保
一旦匹配的语句出现，程序就会跳出 switch
执行并在 switch 之后的语句处继续执行。如果
省略break，程序继续执行下一个
switch语句中的语句。
所以你的代码应该是这样的：
function stepStream(stream,step){
switch (stream[step]){
case "start":
console.log("Started reading stream...");
break;
case "end":
var success = "Finished reading dataStream.";
console.log(success);
return success;
default:
throw "Data stream format is bad";
case "gesture":
//commUGesture(stream[i+1]);
//createLogLine("robot:CommU","event:gesture:"+stream[i+1]);
console.log("Running case gesture! But why?");
step+=1;
stepStream(stream,step);
break;
case "say":
step+=1;
stepStream(stream,step);
break;
case "sleep":
step+=1;
stepStream(stream,step);
break;
}
您的“结束”案例最后有一个返回，因此代码不会落入其他案例。理想情况下，应该有一个break在每个的末尾。
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