使用 lodash/Javascript 对数字数组进行排序

我有一个字符串数组，如下所示。

let arr = ["1", "1+", "1-","2", "2+", "3","3+", "2-", "3-", "4", "10"];

我想要如下的预期输出。

["1+", "1", "1-", "2+", "2", "2-", "3+", "3", "3-", "4", "10"];

我尝试了下面的代码，但它没有给我正确的结果。

let arr = ["1", "1+", "1-","2", "2+", "3","3+", "2-", "3-", "4", "10"];
let result = arr.sort((a,b) => { 
  return a.localeCompare(b, undefined, {
      numeric: true,
      sensitivity: 'base',
    });
  });

console.log(result);

因此，您需要数字和符号的比较器。

一般概念：
您可以像这样定义符号优先级：

const signPriority = {
  '+': 0,
  'n': 1, // n = no sign
  '-': 2,
} 

Where key是符号并且value是我们将在比较器中使用的符号权重（'n'意思是“没有迹象”）。

然后我们将数组元素拆分为数字和符号，在比较器函数中并分别比较它们：

arr.sort((a, b) => { 
    // If numbers are different ...
    if (parseInt(a) !== parseInt(b)) {
        // Just compare a numbers 
        return parseInt(a) - parseInt(b);
    } else {
        // If sign matter ...
        // Extract sign from element or define as 'n' if no sign found
        const sign_a = ['+', '-'].includes(a.slice(-1)) ? a.slice(-1) : 'n';
        const sign_b = ['+', '-'].includes(b.slice(-1)) ? b.slice(-1) : 'n';
        // Compare signs using their weight
        return signPriority[sign_a] - signPriority[sign_b];
    } 
})

完整解决方案：

const signPriority = {
    '+': 0,
    'n': 1,
    '-': 2,
} 

const arr = ["1", "1+", "1-","2", "2+", "3","3+", "2-", "3-", "4", "10"];

const sorted = arr.sort((a, b) => { 
    if (parseInt(a) !== parseInt(b)) {
        return parseInt(a) - parseInt(b);
    } else {
        const sign_a = ['+', '-'].includes(a.slice(-1)) ? a.slice(-1) : 'n';
        const sign_b = ['+', '-'].includes(b.slice(-1)) ? b.slice(-1) : 'n';
        return signPriority[sign_a] - signPriority[sign_b];
    } 
})

console.log(sorted);