我正在使用嵌套列表来查找我创建的字典中的值。然后我想将找到的值附加到列表中。我不知道如何编码的问题是如何将附加的值保留在同一嵌套列表结构中?这是代码,其中最后一行我将值附加到空列表中。
#Creating a dictionary of FID: LU_Codes from external txt file
import sys, arcpy, string, csv
text_file = open("H:\SWAT\NC\FID_Whole.txt", "r")
Lines = text_file.readlines()
text_file.close()
FID_LU = map(string.split, Lines)
#print FID_LU
FID_GC_dict = dict(FID_LU)
Neighbors_file = open("H:\SWAT\NC\Sh_Neighbors2.txt","r")
Entries = Neighbors_file.readlines()
Neighbors_file.close()
Neighbors_List = map(string.split, Entries)
print Neighbors_List
#FID = [x[0] for x in Neighbors_List]
#print FID
gridList = []
for list in Neighbors_List:
for item in list:
#print FID_GC_dict[item]
gridList.append(int(FID_GC_dict[item]))
print gridList
这是邻居列表的输出(正确):
[['0', '1', '11', '12', '13'], ['1', '0', '2', '12', '13', '14'], ['2', '1', '3', '13', '14', '15'], ['3', '2', '4', '14', '15', '16'], ['4', '3', '5', '15', '16', '17'], ['5', '4', '6', '16', '17', '18'], ['6', '5', '7', '17', '18', '19'], ['7', '6', '8', '18', '19', '20'], ['8', '7', '9', '19', '20', '21'], ['9', '8', '20', '21', '22'], ['10', '11']]
这是 gridList 的输出(不正确):
[3, 3, 4, 4, 4, 3, 3, 3, 4, 4, 4, 3, 3, 3, 4, 4, 2, 3, 3, 3, 4, 2, 2, 3, 3, 3, 2, 2, 2, 3, 3, 3, 2, 2, 3, 3, 3, 3, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4]
我希望 gridList 看起来像这样:
[[3, 3, 4, 4, 4], [3, 3, 3, 4, 4, 4], [3, 3, 3, 4, 4, 2], [3, 3, 3, 4, 2, 2], [3, 3, 3, 2, 2, 2], [3, 3, 3, 2, 2, 3], [3, 3, 3, 2, 3, 3], [3, 3, 3, 3, 3, 3], [3, 3, 3, 3, 3, 3], [3, 3, 3, 3, 3], [3, 4]]
任何帮助,将不胜感激。我是 python 新手......阅读帖子有帮助,但我正在努力解决这个问题。
Thanks!