嘿，我正在尝试将 JSON 从 Ajax 发布到 Struts2 操作类方法。更多信息：我在 WAMP 服务器上运行客户端，在 Eclipse Tomcat 上运行 Struts2。
我的客户端代码：
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
var dataObj = {
"data": [{
"id": "1",
"name": "Chris"
}, {
"id": "2",
"name": "Kate"
}, {
"id": "3",
"name": "Blade"
}, {
"id": "4",
"name": "Zack"
}]
};
var data1 = JSON.stringify(dataObj);
$(document).ready(function(){
$("button").click(function(){
$.ajax({url:"http://localhost:8080/Core/add",type: "post", data: data1, dataType: 'json', contentType:"application/json;charset=utf-8",async: true,success:function(result){
$("#div1").html(result);
}});
});
});
</script>
</head>
<body>
<div id="div1"><h2>Let jQuery AJAX Change This Text</h2></div>
<button>Get External Content</button>
</body>
</html>
这是我的 Java 应用程序内容：
struts.xml:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.1.7//EN"
"http://struts.apache.org/dtds/struts-2.1.7.dtd">
<struts>
<package name="addMenu" namespace="/" extends="json-default">
<action name="registrate" class="com.coreRestaurant.menu.MenuAction">
<result type="json" >
<param name="root">json</param>
</result>
</action>
<action name="read" class="com.coreRestaurant.menu.MenuAction" method="readMenuById">
<result type="json" >
<param name="root">json</param>
</result>
</action>
<action name="add" class="com.coreRestaurant.menu.MenuAction" method="addMenu">
<result type="json" >
<param name="root">data</param>
</result>
</action>
</package>
</struts>
这是我的java代码（MenuAction.java):
package com.coreRestaurant.menu;
import java.io.Serializable;
import java.util.ArrayList;
import java.util.List;
import com.google.gson.Gson;
import com.opensymphony.xwork2.ActionSupport;
import com.opensymphony.xwork2.ModelDriven;
public class MenuAction extends ActionSupport implements ModelDriven<Menu>, Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
private Menu menu = new Menu();
private String json;
private List<Menu> data = new ArrayList<Menu>();
public String execute(){
MenuService menuService = new MenuService();
setJson(new Gson().toJson(menuService.getMenuNames()));
if(menuService.isDatabaseConnectionDown()==false){
return SUCCESS;
}else{
setJson(new Gson().toJson("Failed to connect to Database"));
return ERROR;
}
}
public String readMenuById(){
MenuService menuService = new MenuService();
setJson(new Gson().toJson(menuService.getSpecificalMenuNameById(menu.getId())));
return SUCCESS;
}
public String addMenu(){
MenuService menuService = new MenuService();
System.out.println(data);
for(int i=0; i<data.size(); i++){
System.out.println(data.get(i));
}
menu.setName("Postitus");
menuService.addMenu(menu);
return SUCCESS;
}
public String getJson() {
return json;
}
public void setJson(String json) {
this.json = json;
}
@Override
public Menu getModel() {
return menu;
}
public List<Menu> getData() {
System.out.println("Getter Call");
return data;
}
public void setData(List<Menu> data) {
System.out.println("Setter Call Flow");
this.data = data;
}
}
And the Menu.java itself:
package com.coreRestaurant.menu;
import java.io.Serializable;
public class Menu implements Serializable{
private static final long serialVersionUID = 1L;
private String name;
private int id;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
}
当我运行客户端代码时，我只能从 Eclipse 控制台看到以下输入：
[]
Getter Call
为什么是空的？我希望从客户端获得该 JSON 数组，但没有成功。
