如何在 Pygame 中生成第二次点击的位置？

我正在建造河内塔。

它应该像这样工作：您单击第一个塔，从您想要磁盘移动的位置，然后单击第二个塔，您希望磁盘移动到的位置。磁盘应从第一个塔（一个列表）移动到第二个塔（另一个列表）。

我的问题是，当您第一次单击时，代码会生成位置，不久之后您应该再次单击以决定磁盘应该去哪里，但代码会自动采用第一次单击的位置。

这是我的代码示例：

import pygame, sys
from pygame.locals import *

pygame.init()

DISPLAYSURF = pygame.display.set_mode((500, 400))
pygame.display.set_caption("Tower of Hanoi")

block_red = pygame.image.load('red.png')
block_blue = pygame.image.load('blue.png')
block_green = pygame.image.load('green.png')

rod1 = [block_red, block_blue, block_green]
rod2 = []
rod3 = []

WHITE = (255, 255, 255)

while True:

    DISPLAYSURF.fill(WHITE)

    # get the position of the mouse click
    for event in pygame.event.get():
        if event.type == MOUSEBUTTONDOWN:
            mousex, mousey = pygame.mouse.get_pos()
            click1 = mousex, mousey

            # first in the left part of the screen
            if (mousex > 0) and (mousex < 166) and (mousey > 0) and (mousey < 400):

                if len(rod1) == 0:
                    print "not valid"

                elif len(rod1) == 1 or 2 or 3:
                    disk1 = rod1[-1]
                    rod1.remove(disk1)

                    # click again in a other part of the screen
                    if event.type == MOUSEBUTTONDOWN:
                        mousex, mousey = pygame.mouse.get_pos()   
                        click2 = mousex, mousey

                        if (mousex > 166) and (mousex < 333) and (mousey > 0) and (mousey < 400):
                            rod2.append(disk1)
                        elif (mousex > 333) and (mousex < 500) and (mousey > 0) and (mousey < 400):
                            rod3.append(disk1)
                        else: 
                            rod1.append(disk1)

    # if statement fot the middle part
    # if statement for the right part                        

    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
    pygame.display.update()

请记住，您的代码在循环中运行，因此您必须跟踪state你的游戏。

点击第一个塔改变状态游戏的部分：现在选择了一个塔，单击塔现在会执行不同的操作（它将一个块从第一个塔移动到第二个塔）。

在您的示例中，您只需要跟踪当前是否选择塔的事实（当然，以及每个塔具有的块）。不要害怕这个词state，一个简单的变量就足够了。

看一下下面的代码（注意注释）。它只是跟踪变量中选定的杆selected，然后检查是否设置为决定是否需要移动块。

import pygame
from collections import namedtuple

pygame.init()
screen = pygame.display.set_mode((500, 400))

# create a named tuple to keep track of the size/location of the rods and their blocks
Rod = namedtuple('Rod', ['rect', 'items'])

# first rod has 4 items. The just use a number to keep track of the size of the blocks 
rods = (Rod(pygame.rect.Rect((100, 150, 25, 250)), [6, 5, 4, 3, 2, 1]),
        Rod(pygame.rect.Rect((225, 150, 25, 250)), []),
        Rod(pygame.rect.Rect((350, 150, 25, 250)), []))

# keep track of the currently selected rod
selected = None

while True:
    if pygame.event.get(pygame.QUIT): break

    screen.fill(pygame.color.Color('white'))

    # draw the rods. It's easy since every rod has a rect which we can use with pygame.draw.rect
    for rod in rods:
        # if a rod is selected, we draw it yellow instead of black
        pygame.draw.rect(screen, pygame.color.Color('yellow' if selected == rod else 'black'), rod.rect)    
        # draw each block of each rod
        for i, item in enumerate(rod.items):
            r = pygame.rect.Rect(rod.rect.x - item * 8, 375 - 25 * i, 25 + item * 16, 25) 
            pygame.draw.rect(screen, pygame.color.Color('green' if selected == rod else 'darkgreen'), r)    

    for e in pygame.event.get():
        if e.type == pygame.MOUSEBUTTONDOWN:
            # check if we clicked a rod. It's easy since every rod has a rect
            rod = next((r for r in rods if r.rect.collidepoint(pygame.mouse.get_pos())), None)
            if rod:
                if selected:
                    # if there's already a rod selected, move block from one the selected
                    # rod to the clicked rod
                    rod.items.append(selected.items.pop())
                    selected = None
                elif rod.items:
                    # if no rod is selected, selected the currently clicked one (if it has blocks)
                    selected = rod
            else:
                selected = None

    pygame.display.flip()   

Result: