我正在尝试以编程方式创建 xls 工作表。为了填写表格，我正在制作倍数NSURLConnection大约100。现在，我的方法是：
- 建立连接并将数据存储到数组中。该数组有 100 个对象。
- 现在获取第一个对象并调用连接。存储数据。并与数组中的第二个对象建立第二个连接。这一直持续到数组中的最后一个对象。
完成 100 个连接平均需要 14 秒。有没有什么办法可以实现NSURLConnection以更快的方式获得响应？
直到昨天我遵循的基本方法如下：
声明属性：
@property (nonatomic,strong) NSURLConnection *getReportConnection;
@property (retain, nonatomic) NSMutableData *receivedData;
@property (nonatomic,strong) NSMutableArray *reportArray;
初始化数组在viewDidLoad:
reportArray=[[NSMutableArray alloc]init];
初始化NSURLConnection在按钮操作中：
/initialize url that is going to be fetched.
NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"****/%@/crash_reasons",ID]];
//initialize a request from url
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request addValue:tokenReceived forHTTPHeaderField:@"**Token"];
[request setHTTPMethod:@"GET"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
//initialize a connection from request
self.getReportConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
处理接收到的数据：
- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData*)data{
if (connection==_getVersionConnection) {
[self.receivedData_ver appendData:data];
NSString *responseString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSError *e = nil;
NSData *jsonData = [responseString dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *JSON = [NSJSONSerialization JSONObjectWithData:jsonData options: NSJSONReadingMutableContainers error: &e];
[JSON[@"app_versions"] enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
if (![obj[@"id"] isEqual:[NSNull null]] && ![reportArray_ver containsObject:obj[@"id"]]) {
[reportArray_ver addObject:obj[@"id"]];
}
NSLog(@"index = %lu, Object For title Key = %@", (unsigned long)idx, obj[@"id"]);
}];
if (JSON!=nil) {
UIAlertView *alert=[[UIAlertView alloc]initWithTitle:@"Version Reports succesfully retrieved" message:@"" delegate:self cancelButtonTitle:@"Ok" otherButtonTitles: nil];
[alert show];
}
}
}
一个连接完成后调用另一个连接：
// This method is used to process the data after connection has made successfully.
- (void)connectionDidFinishLoading:(NSURLConnection *)connection{
if (connection==getReportConnection) {
//check and call the connection again
}
}
今天，我尝试了NSURLConnection with sendAsync使用循环一个接一个地触发所有连接，效果非常好。
self.receivedData_ver=[[NSMutableData alloc]init];
__block NSInteger outstandingRequests = [reqArray count];
for (NSString *URL in reqArray) {
NSMutableURLRequest *request=[NSMutableURLRequest requestWithURL:[NSURL URLWithString:URL]
cachePolicy:NSURLRequestUseProtocolCachePolicy
timeoutInterval:10.0];
[request setHTTPMethod:@"GET"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[NSURLConnection sendAsynchronousRequest:request
queue:[NSOperationQueue mainQueue]
completionHandler:^(NSURLResponse *response,
NSData *data,
NSError *connectionError) {
[self.receivedData appendData:data]; //What is the use of appending NSdata into Nsmutable data?
NSString *responseString = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSError *e = nil;
NSData *jsonData = [responseString dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *JSON = [NSJSONSerialization JSONObjectWithData:jsonData options: NSJSONReadingMutableContainers error: &e];
NSLog(@"login json is %@",JSON);
[JSON[@"app_versions"] enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
if (![obj[@"id"] isEqual:[NSNull null]] && ![reportArray_ver containsObject:obj[@"id"]]) {
[reportArray_ver addObject:obj[@"id"]];
}
NSLog(@"index = %lu, Object For title Key = %@", (unsigned long)idx, obj[@"id"]);
}];
outstandingRequests--;
if (outstandingRequests == 0) {
//all req are finished
UIAlertView *alert=[[UIAlertView alloc]initWithTitle:@"Version Reports succesfully retrieved" message:@"" delegate:self cancelButtonTitle:@"Ok" otherButtonTitles: nil];
[alert show];
}
}];
}
这次完成 100 个请求的时间比旧程序减少了一半，除了 asynReq 之外还有其他更快的方法吗？最好的使用场景是什么NSURLconnection and NSURLConnection with asyncReq?
