我正在编写一个批处理脚本，我需要 unix 时间。在linux下很容易，但我不知道如何在windows下做到这一点。
这是一个适用于任何区域设置的本机批处理解决方案。它使用 WMIC 以与区域设置无关的方式获取当前本地时间。其他一切都是字符串解析和基本数学的“简单”问题。
:UnixTime [ReturnVar] [TimeStamp]
::
:: Computes the Unix time from the current local time as reported by the
:: operating system. The Unix time is the number of seconds that have elapsed
:: since midnight Coordinated Universal Time (UTC), January 1, 1970, not
:: counting leap seconds.
::
:: The result is returned in variable ReturnVar,
:: or the result is echoed if ReturnVar is not specified
::
:: If the TimeStamp is provided in the 2nd parameter, then the Unix time for
:: the TimeStamp is computed, rather then for the current time.
::
:: The TimeStamp must have the same format as used by WMIC:
::
:: YYYYMMDDhhmmss.ffffffSzzz
::
:: where:
::
:: YYYY = gregorian year
:: MM = month
:: DD = day
:: hh = hour in 24 hour format
:: mm = minute
:: ss = seconds
:: ffffff = fractional seconds (microseconds)
:: S = timezone sign: + or -
:: zzz = timezone: minutes difference from GMT
::
:: Each component must be zero prefixed as needed to maintain the proper width.
::
:: The ReturnVar parameter must be provided in order to use the TimeStamp.
:: A ReturnVar of "" will function the same as no ReturnVar. This enables the
:: specification of a TimeStamp without an actual ReturnVar.
::
@echo off
setlocal
set "ts=%~2"
if not defined ts for /f "skip=1 delims=" %%A in ('wmic os get localdatetime') do if not defined ts set "ts=%%A"
set /a "yy=10000%ts:~0,4% %% 10000, mm=100%ts:~4,2% %% 100, dd=100%ts:~6,2% %% 100"
set /a "dd=dd-2472663+1461*(yy+4800+(mm-14)/12)/4+367*(mm-2-(mm-14)/12*12)/12-3*((yy+4900+(mm-14)/12)/100)/4"
set /a ss=(((1%ts:~8,2%*60)+1%ts:~10,2%)*60)+1%ts:~12,2%-366100-%ts:~21,1%((1%ts:~22,3%*60)-60000)
set /a ss+=dd*86400
endlocal & if "%~1" neq "" (set %~1=%ss%) else echo %ss%
exit /b
请注意，该解决方案的使用寿命有限。当 Unix 时间超过有符号 32 位整数的最大值时，它将在 2038 年 1 月 19 日停止工作。
EDIT
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