Python字符串转为字典方法大全

2023-11-11

方法一: 通过内置函数eval

str_info = '{"name": "test", "age": 18}'

dict_info = eval(str_info)

print("string info type is -->: %s" % (type(str_info)))

print("dict info type is -->: %s" % (type(dict_info)))

print(dict_info)

s_info = "{'name': 'nock', 'age': 18}"

d_info = eval(s_info)

print("string info type is -->: %s" % (type(s_info)))

print("dict info type is -->: %s" % (type(d_info)))

print(d_info)

F:\python\python35\python.exe E:/code/clself/Test/test_example1.py

string info type is -->: <class 'str'>

dict info type is -->: <class 'dict'>

{'name': 'test', 'age': 18}

string info type is -->: <class 'str'>

dict info type is -->: <class 'dict'>

{'name': 'nock', 'age': 18}

Process finished with exit code 0

不过使用eval有一个安全性问题

方法二: 通过json模块处理

import json

str_info = '{"name": "test", "age": 18}'

dict_info = json.loads(str_info)

print("string info type is -->: %s" % (type(str_info)))

print("dict info type is -->: %s" % (type(dict_info)))

print(dict_info)

s_info = "{'name': 'nock', 'age': 18}"

d_info = json.loads(s_info)

print("s info type is -->: %s" % (type(s_info)))

print("d info type is -->: %s" % (type(d_info)))

print(d_info)

结果如下：

F:\python\python35\python.exe E:/code/clself/Test/test_example1.py

string info type is -->: <class 'str'>

dict info type is -->: <class 'dict'>

{'name': 'test', 'age': 18}

Traceback (most recent call last):

File "E:/code/clself/Test/test_example1.py", line 10, in <module>

d_info = json.loads(s_info)

File "F:\python\python35\lib\json\__init__.py", line 319, in loads

return _default_decoder.decode(s)

File "F:\python\python35\lib\json\decoder.py", line 339, in decode

obj, end = self.raw_decode(s, idx=_w(s, 0).end())

File "F:\python\python35\lib\json\decoder.py", line 355, in raw_decode

obj, end = self.scan_once(s, idx)

json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes: line 1 column 2 (char 1)

Process finished with exit code 1

使用json模块进行转换存在一个问题,由于json语法规定数组或对象之中的字符串必须使用双引号，不能使用单引号

方法三: 通过ast模块处理【推荐使用】

复制代码

import ast
str_info = '{"name": "test", "age": 18}'
dict_info = ast.literal_eval(str_info)

print("string info type is -->: %s" % (type(str_info)))
print("dict info type is -->: %s" % (type(dict_info)))
print(dict_info)

s_info = "{'name': 'nock', 'age': 18}"
d_info = ast.literal_eval(s_info)

print("s info type is -->: %s" % (type(s_info)))
print("d info type is -->: %s" % (type(d_info)))
print(d_info)

复制代码

F:\python\python35\python.exe E:/code/clself/Test/test_example1.py

string info type is -->: <class 'str'>

dict info type is -->: <class 'dict'>

{'name': 'test', 'age': 18}

s info type is -->: <class 'str'>

d info type is -->: <class 'dict'>

{'name': 'test', 'age': 18}

使用ast.literal_eval进行转换既不存在使用json 模块进行转换的问题，也不存在使用eval模块进行转换的安全性问题，因此推荐大家使用ast.literal_eval的方法。

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