【每日一题-13】二叉树中查找节点/子树

在二叉树中查找一个节点

struct TreeNode
{
	int data;
	TreeNode* left;
	TreeNode* right;
	TreeNode(int val)
		: data(val)
		, left(NULL)
		, right(NULL)
	{}
};
bool FindNode(TreeNode* root, TreeNode* node)
{
	if (NULL == root)
		return false;
	if (root->data == node->data)
		return true;
	return FindNode(root->left, node) || FindNode(root->right, node);
}

bool hasSubTree(TreeNode* root1, TreeNode* root2)
{
	if (root1 == NULL || root2 == NULL)
		return false;
	if (root1->data == root2->data)
	{
		if (isSubTree(root1, root2))
			return true;
	}
	return hasSubTree(root1->left, root2) || hasSubTree(root1->right, root2);
}

bool isSubTree(TreeNode* root1, TreeNode* root2)
{
	if (root1 == NULL)
		return true;
	if (root2 == NULL)
		return false;
	if (root1->data != root2->data)
		return false;
	return isSubTree(root1->left, root2->left) && isSubTree(root1->right, root2->right);
}